Base | Representation |
---|---|
bin | 11001111110001001100100… |
… | …011000000111011001111011 |
3 | 112222102112001122210022022111 |
4 | 121332021210120013121323 |
5 | 104432403221321010321 |
6 | 1042532514402033151 |
7 | 33026161511166502 |
oct | 3176114430073173 |
9 | 488375048708274 |
10 | 114222044313211 |
11 | 3343832a28582a |
12 | 10988bb76487b7 |
13 | 4b97128484b73 |
14 | 202c53ad59839 |
15 | d3129e0c55e1 |
hex | 67e26460767b |
114222044313211 has 2 divisors, whose sum is σ = 114222044313212. Its totient is φ = 114222044313210.
The previous prime is 114222044313203. The next prime is 114222044313217. The reversal of 114222044313211 is 112313440222411.
It is a strong prime.
It is an emirp because it is prime and its reverse (112313440222411) is a distict prime.
It is a cyclic number.
It is not a de Polignac number, because 114222044313211 - 23 = 114222044313203 is a prime.
It is not a weakly prime, because it can be changed into another prime (114222044313217) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 57111022156605 + 57111022156606.
It is an arithmetic number, because the mean of its divisors is an integer number (57111022156606).
Almost surely, 2114222044313211 is an apocalyptic number.
114222044313211 is a deficient number, since it is larger than the sum of its proper divisors (1).
114222044313211 is an equidigital number, since it uses as much as digits as its factorization.
114222044313211 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 9216, while the sum is 31.
Adding to 114222044313211 its reverse (112313440222411), we get a palindrome (226535484535622).
The spelling of 114222044313211 in words is "one hundred fourteen trillion, two hundred twenty-two billion, forty-four million, three hundred thirteen thousand, two hundred eleven".
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