Base | Representation |
---|---|
bin | 11001111110001001100100… |
… | …011000100100011010001011 |
3 | 112222102112001200000100021111 |
4 | 121332021210120210122023 |
5 | 104432403221333311021 |
6 | 1042532514404351151 |
7 | 33026161512203035 |
oct | 3176114430443213 |
9 | 488375050010244 |
10 | 114222044432011 |
11 | 3343832a35700a |
12 | 10988bb76a54b7 |
13 | 4b971284c6c69 |
14 | 202c53ad8ac55 |
15 | d3129e0ea8e1 |
hex | 67e26462468b |
114222044432011 has 4 divisors (see below), whose sum is σ = 115043785759000. Its totient is φ = 113400303105024.
The previous prime is 114222044432009. The next prime is 114222044432071. The reversal of 114222044432011 is 110234440222411.
It is a semiprime because it is the product of two primes.
It is a cyclic number.
It is not a de Polignac number, because 114222044432011 - 21 = 114222044432009 is a prime.
It is a Duffinian number.
It is not an unprimeable number, because it can be changed into a prime (114222044432071) by changing a digit.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 410870663286 + ... + 410870663563.
It is an arithmetic number, because the mean of its divisors is an integer number (28760946439750).
Almost surely, 2114222044432011 is an apocalyptic number.
114222044432011 is a deficient number, since it is larger than the sum of its proper divisors (821741326989).
114222044432011 is an equidigital number, since it uses as much as digits as its factorization.
114222044432011 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 821741326988.
The product of its (nonzero) digits is 12288, while the sum is 31.
Adding to 114222044432011 its reverse (110234440222411), we get a palindrome (224456484654422).
The spelling of 114222044432011 in words is "one hundred fourteen trillion, two hundred twenty-two billion, forty-four million, four hundred thirty-two thousand, eleven".
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