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115032224242931 is a prime number
BaseRepresentation
bin11010001001111100000110…
…110111010001110011110011
3120002021222021111021001121012
4122021330012313101303303
5110034141443401233211
61044353024013421135
733141542516030102
oct3211740667216363
9502258244231535
10115032224242931
113371a98a779386
1210a9a02319a7ab
134c25652499898
1420598372c0039
15d473bae67d8b
hex689f06dd1cf3

115032224242931 has 2 divisors, whose sum is σ = 115032224242932. Its totient is φ = 115032224242930.

The previous prime is 115032224242919. The next prime is 115032224242933. The reversal of 115032224242931 is 139242422230511.

It is a strong prime.

It is an emirp because it is prime and its reverse (139242422230511) is a distict prime.

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2k-115032224242931 is a prime.

It is a super-2 number, since 2×1150322242429312 (a number of 29 digits) contains 22 as substring.

Together with 115032224242933, it forms a pair of twin primes.

It is a Chen prime.

It is not a weakly prime, because it can be changed into another prime (115032224242933) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 57516112121465 + 57516112121466.

It is an arithmetic number, because the mean of its divisors is an integer number (57516112121466).

Almost surely, 2115032224242931 is an apocalyptic number.

115032224242931 is a deficient number, since it is larger than the sum of its proper divisors (1).

115032224242931 is an equidigital number, since it uses as much as digits as its factorization.

115032224242931 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 207360, while the sum is 41.

The spelling of 115032224242931 in words is "one hundred fifteen trillion, thirty-two billion, two hundred twenty-four million, two hundred forty-two thousand, nine hundred thirty-one".