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BaseRepresentation
bin11010001001111100000110…
…110111010010000011001101
3120002021222021111021002221201
4122021330012313102003031
5110034141443401301132
61044353024013425501
733141542516033011
oct3211740667220315
9502258244232851
10115032224243917
113371a98a77a0a2
1210a9a02319b291
134c2565249a176
1420598372c0541
15d473bae682e7
hex689f06dd20cd

115032224243917 has 2 divisors, whose sum is σ = 115032224243918. Its totient is φ = 115032224243916.

The previous prime is 115032224243843. The next prime is 115032224243957. The reversal of 115032224243917 is 719342422230511.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 97543652263561 + 17488571980356 = 9876419^2 + 4181934^2 .

It is a cyclic number.

It is not a de Polignac number, because 115032224243917 - 27 = 115032224243789 is a prime.

It is a super-2 number, since 2×1150322242439172 (a number of 29 digits) contains 22 as substring.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (115032224243957) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (23) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 57516112121958 + 57516112121959.

It is an arithmetic number, because the mean of its divisors is an integer number (57516112121959).

Almost surely, 2115032224243917 is an apocalyptic number.

It is an amenable number.

115032224243917 is a deficient number, since it is larger than the sum of its proper divisors (1).

115032224243917 is an equidigital number, since it uses as much as digits as its factorization.

115032224243917 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 725760, while the sum is 46.

The spelling of 115032224243917 in words is "one hundred fifteen trillion, thirty-two billion, two hundred twenty-four million, two hundred forty-three thousand, nine hundred seventeen".