Base | Representation |
---|---|
bin | 11010001001111100000110… |
… | …110111010010000011110011 |
3 | 120002021222021111021010000010 |
4 | 122021330012313102003303 |
5 | 110034141443401301310 |
6 | 1044353024013430003 |
7 | 33141542516033064 |
oct | 3211740667220363 |
9 | 502258244233003 |
10 | 115032224243955 |
11 | 3371a98a77a127 |
12 | 10a9a02319b303 |
13 | 4c2565249a1a5 |
14 | 20598372c056b |
15 | d473bae68320 |
hex | 689f06dd20f3 |
115032224243955 has 64 divisors (see below), whose sum is σ = 203354119987200. Its totient is φ = 55230333413376.
The previous prime is 115032224243917. The next prime is 115032224243957. The reversal of 115032224243955 is 559342422230511.
It is not a de Polignac number, because 115032224243955 - 210 = 115032224242931 is a prime.
It is a super-2 number, since 2×1150322242439552 (a number of 29 digits) contains 22 as substring.
It is not an unprimeable number, because it can be changed into a prime (115032224243957) by changing a digit.
It is a polite number, since it can be written in 63 ways as a sum of consecutive naturals, for example, 607419621 + ... + 607608969.
It is an arithmetic number, because the mean of its divisors is an integer number (3177408124800).
Almost surely, 2115032224243955 is an apocalyptic number.
115032224243955 is a gapful number since it is divisible by the number (15) formed by its first and last digit.
115032224243955 is a deficient number, since it is larger than the sum of its proper divisors (88321895743245).
115032224243955 is a wasteful number, since it uses less digits than its factorization.
115032224243955 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 292980.
The product of its (nonzero) digits is 2592000, while the sum is 48.
The spelling of 115032224243955 in words is "one hundred fifteen trillion, thirty-two billion, two hundred twenty-four million, two hundred forty-three thousand, nine hundred fifty-five".
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