Base | Representation |
---|---|
bin | 11010001001111100000110… |
… | …110111010010001101000111 |
3 | 120002021222021111021010211012 |
4 | 122021330012313102031013 |
5 | 110034141443401311201 |
6 | 1044353024013432435 |
7 | 33141542516034605 |
oct | 3211740667221507 |
9 | 502258244233735 |
10 | 115032224244551 |
11 | 3371a98a77a619 |
12 | 10a9a02319b71b |
13 | 4c2565249a543 |
14 | 20598372c0875 |
15 | d473bae685bb |
hex | 689f06dd2347 |
115032224244551 has 2 divisors, whose sum is σ = 115032224244552. Its totient is φ = 115032224244550.
The previous prime is 115032224244527. The next prime is 115032224244577. The reversal of 115032224244551 is 155442422230511.
It is a weak prime.
It is a cyclic number.
It is not a de Polignac number, because 115032224244551 - 214 = 115032224228167 is a prime.
It is a super-2 number, since 2×1150322242445512 (a number of 29 digits) contains 22 as substring.
It is a junction number, because it is equal to n+sod(n) for n = 115032224244499 and 115032224244508.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (115032224244251) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 57516112122275 + 57516112122276.
It is an arithmetic number, because the mean of its divisors is an integer number (57516112122276).
Almost surely, 2115032224244551 is an apocalyptic number.
115032224244551 is a deficient number, since it is larger than the sum of its proper divisors (1).
115032224244551 is an equidigital number, since it uses as much as digits as its factorization.
115032224244551 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 384000, while the sum is 41.
The spelling of 115032224244551 in words is "one hundred fifteen trillion, thirty-two billion, two hundred twenty-four million, two hundred forty-four thousand, five hundred fifty-one".
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