115141207 has 2 divisors, whose sum is σ = 115141208. Its totient is φ = 115141206.

The previous prime is 115141199. The next prime is 115141217. The reversal of 115141207 is 702141511.

It is a weak prime.

It is an emirp because it is prime and its reverse (702141511) is a distict prime.

It is a cyclic number.

It is not a de Polignac number, because 115141207 - 2³ = 115141199 is a prime.

It is a Chen prime.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (115141217) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (17) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 57570603 + 57570604.

It is an arithmetic number, because the mean of its divisors is an integer number (57570604).

Almost surely, 2^115141207 is an apocalyptic number.

115141207 is a deficient number, since it is larger than the sum of its proper divisors (1).

115141207 is an equidigital number, since it uses as much as digits as its factorization.

115141207 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 280, while the sum is 22.

The square root of 115141207 is about 10730.3870852826. The cubic root of 115141207 is about 486.4933698885.

Adding to 115141207 its reverse (702141511), we get a palindrome (817282718).

It can be divided in two parts, 11514 and 1207, that added together give a palindrome (12721).

The spelling of 115141207 in words is "one hundred fifteen million, one hundred forty-one thousand, two hundred seven".