Base | Representation |
---|---|
bin | 10000110010010101001… |
… | …100011111000000011101 |
3 | 11002021112011221202111220 |
4 | 100302111030133000131 |
5 | 122344434401010440 |
6 | 2241534024203553 |
7 | 146225102610405 |
oct | 20622514370035 |
9 | 4067464852456 |
10 | 1153554313245 |
11 | 405246378204 |
12 | 1676970095b9 |
13 | 84a1a020019 |
14 | 3db91c93805 |
15 | 200173d08d0 |
hex | 10c9531f01d |
1153554313245 has 16 divisors (see below), whose sum is σ = 1846118945472. Its totient is φ = 615084952320.
The previous prime is 1153554313159. The next prime is 1153554313277. The reversal of 1153554313245 is 5423134553511.
It is not a de Polignac number, because 1153554313245 - 211 = 1153554311197 is a prime.
It is a super-2 number, since 2×11535543132452 (a number of 25 digits) contains 22 as substring.
It is a junction number, because it is equal to n+sod(n) for n = 1153554313197 and 1153554313206.
It is a congruent number.
It is an unprimeable number.
It is a polite number, since it can be written in 15 ways as a sum of consecutive naturals, for example, 8934691 + ... + 9062880.
It is an arithmetic number, because the mean of its divisors is an integer number (115382434092).
Almost surely, 21153554313245 is an apocalyptic number.
1153554313245 is a gapful number since it is divisible by the number (15) formed by its first and last digit.
It is an amenable number.
1153554313245 is a deficient number, since it is larger than the sum of its proper divisors (692564632227).
1153554313245 is a wasteful number, since it uses less digits than its factorization.
1153554313245 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 18001852.
The product of its digits is 540000, while the sum is 42.
Adding to 1153554313245 its reverse (5423134553511), we get a palindrome (6576688866756).
The spelling of 1153554313245 in words is "one trillion, one hundred fifty-three billion, five hundred fifty-four million, three hundred thirteen thousand, two hundred forty-five".
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