Base | Representation |
---|---|
bin | 110101101111011001… |
… | …0110001001010000001 |
3 | 102000212220122001020111 |
4 | 1223132302301022001 |
5 | 3342323143001233 |
6 | 125003420311321 |
7 | 11223615213262 |
oct | 1533662611201 |
9 | 360786561214 |
10 | 115407000193 |
11 | 44a42274411 |
12 | 1a4496a2541 |
13 | ab6277b3c4 |
14 | 582b34c969 |
15 | 3006b46acd |
hex | 1adecb1281 |
115407000193 has 4 divisors (see below), whose sum is σ = 115530167620. Its totient is φ = 115283832768.
The previous prime is 115407000143. The next prime is 115407000223. The reversal of 115407000193 is 391000704511.
It is the 138689-th star number.
It is a semiprime because it is the product of two primes.
It can be written as a sum of positive squares in 2 ways, for example, as 49700905969 + 65706094224 = 222937^2 + 256332^2 .
It is a cyclic number.
It is not a de Polignac number, because 115407000193 - 217 = 115406869121 is a prime.
It is a Duffinian number.
It is not an unprimeable number, because it can be changed into a prime (115407000143) by changing a digit.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 61582308 + ... + 61584181.
It is an arithmetic number, because the mean of its divisors is an integer number (28882541905).
Almost surely, 2115407000193 is an apocalyptic number.
It is an amenable number.
115407000193 is a deficient number, since it is larger than the sum of its proper divisors (123167427).
115407000193 is an equidigital number, since it uses as much as digits as its factorization.
115407000193 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 123167426.
The product of its (nonzero) digits is 3780, while the sum is 31.
The spelling of 115407000193 in words is "one hundred fifteen billion, four hundred seven million, one hundred ninety-three", and thus it is an aban number.
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