Base | Representation |
---|---|
bin | 1010100011111110101101… |
… | …0110011011011011000111 |
3 | 1112010012211000112212101120 |
4 | 2220333223112123123013 |
5 | 3010232411223020333 |
6 | 40411015014525023 |
7 | 2306013016562130 |
oct | 250775326333307 |
9 | 45105730485346 |
10 | 11613245126343 |
11 | 3778171131a13 |
12 | 1376884366773 |
13 | 66318017a513 |
14 | 2c2126952c87 |
15 | 152149248db3 |
hex | a8feb59b6c7 |
11613245126343 has 8 divisors (see below), whose sum is σ = 17696373525888. Its totient is φ = 6636140072184.
The previous prime is 11613245126311. The next prime is 11613245126363. The reversal of 11613245126343 is 34362154231611.
It is a sphenic number, since it is the product of 3 distinct primes.
It is not a de Polignac number, because 11613245126343 - 25 = 11613245126311 is a prime.
It is a junction number, because it is equal to n+sod(n) for n = 11613245126295 and 11613245126304.
It is a congruent number.
It is not an unprimeable number, because it can be changed into a prime (11613245126303) by changing a digit.
It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 276505836321 + ... + 276505836362.
It is an arithmetic number, because the mean of its divisors is an integer number (2212046690736).
Almost surely, 211613245126343 is an apocalyptic number.
11613245126343 is a deficient number, since it is larger than the sum of its proper divisors (6083128399545).
11613245126343 is an equidigital number, since it uses as much as digits as its factorization.
11613245126343 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 553011672693.
The product of its digits is 311040, while the sum is 42.
Adding to 11613245126343 its reverse (34362154231611), we get a palindrome (45975399357954).
The spelling of 11613245126343 in words is "eleven trillion, six hundred thirteen billion, two hundred forty-five million, one hundred twenty-six thousand, three hundred forty-three".
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