Base | Representation |
---|---|
bin | 10101110101101110… |
… | …10101000010000001 |
3 | 1010021010122202102010 |
4 | 22322313111002001 |
5 | 143003100011313 |
6 | 5215243243133 |
7 | 563361601620 |
oct | 127267250201 |
9 | 33233582363 |
10 | 11725000833 |
11 | 4a77503737 |
12 | 23328194a9 |
13 | 114b1ab420 |
14 | 7d32b56b7 |
15 | 48954e4c3 |
hex | 2badd5081 |
11725000833 has 64 divisors (see below), whose sum is σ = 20344217600. Its totient is φ = 5832933120.
The previous prime is 11725000801. The next prime is 11725000867. The reversal of 11725000833 is 33800052711.
It is not a de Polignac number, because 11725000833 - 25 = 11725000801 is a prime.
It is a self number, because there is not a number n which added to its sum of digits gives 11725000833.
It is not an unprimeable number, because it can be changed into a prime (11725000883) by changing a digit.
It is a polite number, since it can be written in 63 ways as a sum of consecutive naturals, for example, 1182888 + ... + 1192758.
It is an arithmetic number, because the mean of its divisors is an integer number (317878400).
Almost surely, 211725000833 is an apocalyptic number.
11725000833 is a gapful number since it is divisible by the number (13) formed by its first and last digit.
11725000833 is the 62517-th octagonal number.
It is an amenable number.
11725000833 is a deficient number, since it is larger than the sum of its proper divisors (8619216767).
11725000833 is a wasteful number, since it uses less digits than its factorization.
11725000833 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 10142.
The product of its (nonzero) digits is 5040, while the sum is 30.
It can be divided in two parts, 1172 and 5000833, that added together give a palindrome (5002005).
The spelling of 11725000833 in words is "eleven billion, seven hundred twenty-five million, eight hundred thirty-three", and thus it is an aban number.
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