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118401050753 is a prime number
BaseRepresentation
bin110111001000101000…
…0001010100010000001
3102022121120110120110222
41232101100022202001
53414441132111003
6130220453232425
711361042216536
oct1562120124201
9368546416428
10118401050753
1146239340967
121ab44332715
13b21bb5b95b
145a32c46d8d
15312e912c38
hex1b9140a881

118401050753 has 2 divisors, whose sum is σ = 118401050754. Its totient is φ = 118401050752.

The previous prime is 118401050749. The next prime is 118401050759. The reversal of 118401050753 is 357050104811.

It is a weak prime.

It can be written as a sum of positive squares in only one way, i.e., 104996737024 + 13404313729 = 324032^2 + 115777^2 .

It is an emirp because it is prime and its reverse (357050104811) is a distict prime.

It is a cyclic number.

It is not a de Polignac number, because 118401050753 - 22 = 118401050749 is a prime.

It is a super-3 number, since 3×1184010507533 (a number of 34 digits) contains 333 as substring.

It is not a weakly prime, because it can be changed into another prime (118401050759) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (13) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 59200525376 + 59200525377.

It is an arithmetic number, because the mean of its divisors is an integer number (59200525377).

Almost surely, 2118401050753 is an apocalyptic number.

It is an amenable number.

118401050753 is a deficient number, since it is larger than the sum of its proper divisors (1).

118401050753 is an equidigital number, since it uses as much as digits as its factorization.

118401050753 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 16800, while the sum is 35.

The spelling of 118401050753 in words is "one hundred eighteen billion, four hundred one million, fifty thousand, seven hundred fifty-three".