Base | Representation |
---|---|
bin | 10110010101100111… |
… | …11101101101000110 |
3 | 1010221210002212210011 |
4 | 23022303331231012 |
5 | 144030043214220 |
6 | 5302002020434 |
7 | 603121013122 |
oct | 131263755506 |
9 | 33853085704 |
10 | 11992554310 |
11 | 50a4536610 |
12 | 23a834771a |
13 | 11917587a9 |
14 | 81aa40582 |
15 | 4a2c9e65a |
hex | 2cacfdb46 |
11992554310 has 64 divisors (see below), whose sum is σ = 24130151424. Its totient is φ = 4253932800.
The previous prime is 11992554283. The next prime is 11992554317. The reversal of 11992554310 is 1345529911.
It is a super-2 number, since 2×119925543102 (a number of 21 digits) contains 22 as substring.
It is a Smith number, since the sum of its digits (40) coincides with the sum of the digits of its prime factors. Since it is squarefree, it is also a hoax number.
It is a congruent number.
It is not an unprimeable number, because it can be changed into a prime (11992554317) by changing a digit.
It is a polite number, since it can be written in 31 ways as a sum of consecutive naturals, for example, 1614505 + ... + 1621915.
It is an arithmetic number, because the mean of its divisors is an integer number (377033616).
Almost surely, 211992554310 is an apocalyptic number.
11992554310 is a gapful number since it is divisible by the number (10) formed by its first and last digit.
11992554310 is an abundant number, since it is smaller than the sum of its proper divisors (12137597114).
It is a pseudoperfect number, because it is the sum of a subset of its proper divisors.
11992554310 is a wasteful number, since it uses less digits than its factorization.
11992554310 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 7789.
The product of its (nonzero) digits is 48600, while the sum is 40.
The spelling of 11992554310 in words is "eleven billion, nine hundred ninety-two million, five hundred fifty-four thousand, three hundred ten".
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