12000433 has 2 divisors, whose sum is σ = 12000434. Its totient is φ = 12000432.

The previous prime is 12000431. The next prime is 12000467. The reversal of 12000433 is 33400021.

It is a weak prime.

It can be written as a sum of positive squares in only one way, i.e., 6906384 + 5094049 = 2628^2 + 2257^2 .

It is an emirp because it is prime and its reverse (33400021) is a distict prime.

It is a cyclic number.

It is not a de Polignac number, because 12000433 - 2¹ = 12000431 is a prime.

Together with 12000431, it forms a pair of twin primes.

It is not a weakly prime, because it can be changed into another prime (12000431) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (13) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 6000216 + 6000217.

It is an arithmetic number, because the mean of its divisors is an integer number (6000217).

Almost surely, 2^12000433 is an apocalyptic number.

It is an amenable number.

12000433 is a deficient number, since it is larger than the sum of its proper divisors (1).

12000433 is an equidigital number, since it uses as much as digits as its factorization.

12000433 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 72, while the sum is 13.

The square root of 12000433 is about 3464.1641127406. The cubic root of 12000433 is about 228.9456021513.

Adding to 12000433 its reverse (33400021), we get a palindrome (45400454).

The spelling of 12000433 in words is "twelve million, four hundred thirty-three", and thus it is an aban number.