Base | Representation |
---|---|
bin | 10110010110101000… |
… | …01011101001000011 |
3 | 1010222100222222002121 |
4 | 23023110023221003 |
5 | 144034224000003 |
6 | 5302503025111 |
7 | 603252550126 |
oct | 131324135103 |
9 | 33870888077 |
10 | 12001000003 |
11 | 50a9284a23 |
12 | 23ab13b197 |
13 | 1193424a45 |
14 | 81bbdc3bd |
15 | 4a38bbcbd |
hex | 2cb50ba43 |
12001000003 has 2 divisors, whose sum is σ = 12001000004. Its totient is φ = 12001000002.
The previous prime is 12000999973. The next prime is 12001000031. The reversal of 12001000003 is 30000010021.
It is a strong prime.
It is an emirp because it is prime and its reverse (30000010021) is a distict prime.
It is a cyclic number.
It is not a de Polignac number, because 12001000003 - 213 = 12000991811 is a prime.
It is a self number, because there is not a number n which added to its sum of digits gives 12001000003.
It is not a weakly prime, because it can be changed into another prime (12001000073) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 6000500001 + 6000500002.
It is an arithmetic number, because the mean of its divisors is an integer number (6000500002).
Almost surely, 212001000003 is an apocalyptic number.
12001000003 is a deficient number, since it is larger than the sum of its proper divisors (1).
12001000003 is an equidigital number, since it uses as much as digits as its factorization.
12001000003 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 6, while the sum is 7.
Adding to 12001000003 its reverse (30000010021), we get a palindrome (42001010024).
The spelling of 12001000003 in words is "twelve billion, one million, three", and thus it is an aban number and an uban number.
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