Base | Representation |
---|---|
bin | 11011010010100011001101… |
… | …110111100000100101101001 |
3 | 120201221222210221021221101220 |
4 | 123102203031313200211221 |
5 | 111212420044110000410 |
6 | 1103133204345532253 |
7 | 34165206354122166 |
oct | 3322431567404551 |
9 | 521858727257356 |
10 | 120022020000105 |
11 | 35274064360203 |
12 | 115650a37a4089 |
13 | 51c8049462132 |
14 | 218d14d73906d |
15 | dd20ac8d5070 |
hex | 6d28cdde0969 |
120022020000105 has 64 divisors (see below), whose sum is σ = 193872415942656. Its totient is φ = 63401292864000.
The previous prime is 120022020000073. The next prime is 120022020000167. The reversal of 120022020000105 is 501000020220021.
It is not a de Polignac number, because 120022020000105 - 25 = 120022020000073 is a prime.
It is a super-2 number, since 2×1200220200001052 (a number of 29 digits) contains 22 as substring.
It is a Harshad number since it is a multiple of its sum of digits (15).
It is an unprimeable number.
It is a polite number, since it can be written in 63 ways as a sum of consecutive naturals, for example, 4149981045 + ... + 4150009965.
It is an arithmetic number, because the mean of its divisors is an integer number (3029256499104).
Almost surely, 2120022020000105 is an apocalyptic number.
120022020000105 is a gapful number since it is divisible by the number (15) formed by its first and last digit.
It is an amenable number.
120022020000105 is a deficient number, since it is larger than the sum of its proper divisors (73850395942551).
120022020000105 is a wasteful number, since it uses less digits than its factorization.
120022020000105 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 33038.
The product of its (nonzero) digits is 80, while the sum is 15.
Adding to 120022020000105 its reverse (501000020220021), we get a palindrome (621022040220126).
The spelling of 120022020000105 in words is "one hundred twenty trillion, twenty-two billion, twenty million, one hundred five", and thus it is an aban number.
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