Base | Representation |
---|---|
bin | 10001011101111000001… |
… | …111100011110001101001 |
3 | 11020202012220002100022122 |
4 | 101131320033203301221 |
5 | 124131220141021301 |
6 | 2315225530001025 |
7 | 152501611013324 |
oct | 21357017436151 |
9 | 4222186070278 |
10 | 1200313220201 |
11 | 423060580067 |
12 | 174766576175 |
13 | 8925c463cc4 |
14 | 42149d7d7bb |
15 | 2135245b81b |
hex | 117783e3c69 |
1200313220201 has 8 divisors (see below), whose sum is σ = 1203491520000. Its totient is φ = 1197135841600.
The previous prime is 1200313220173. The next prime is 1200313220251. The reversal of 1200313220201 is 1020223130021.
It is a sphenic number, since it is the product of 3 distinct primes.
It is a cyclic number.
It is a de Polignac number, because none of the positive numbers 2k-1200313220201 is a prime.
It is a Duffinian number.
It is a self number, because there is not a number n which added to its sum of digits gives 1200313220201.
It is not an unprimeable number, because it can be changed into a prime (1200313220251) by changing a digit.
It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 2419400 + ... + 2872998.
It is an arithmetic number, because the mean of its divisors is an integer number (150436440000).
Almost surely, 21200313220201 is an apocalyptic number.
It is an amenable number.
1200313220201 is a deficient number, since it is larger than the sum of its proper divisors (3178299799).
1200313220201 is an equidigital number, since it uses as much as digits as its factorization.
1200313220201 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 460599.
The product of its (nonzero) digits is 144, while the sum is 17.
Adding to 1200313220201 its reverse (1020223130021), we get a palindrome (2220536350222).
The spelling of 1200313220201 in words is "one trillion, two hundred billion, three hundred thirteen million, two hundred twenty thousand, two hundred one".
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