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120130000000002 = 2326673888888889
BaseRepresentation
bin11011010100000111110001…
…111110100001010000000010
3120202100022112020201021120100
4123110013301332201100002
5111221202220000000002
61103254543220023230
734206051250021416
oct3324076176412002
9522308466637510
10120130000000002
1135305935243343
1211581bb9b31b16
1352052973014b5
142194474538d46
15dd4ccc4b911c
hex6d41f1fa1402

120130000000002 has 12 divisors (see below), whose sum is σ = 260281666666710. Its totient is φ = 40043333333328.

The previous prime is 120129999999991. The next prime is 120130000000027. The reversal of 120130000000002 is 200000000031021.

It is a happy number.

It can be written as a sum of positive squares in only one way, i.e., 96699472620921 + 23430527379081 = 9833589^2 + 4840509^2 .

It is a Harshad number since it is a multiple of its sum of digits (9).

It is an unprimeable number.

It is a polite number, since it can be written in 5 ways as a sum of consecutive naturals, for example, 3336944444427 + ... + 3336944444462.

Almost surely, 2120130000000002 is an apocalyptic number.

120130000000002 is an abundant number, since it is smaller than the sum of its proper divisors (140151666666708).

It is a pseudoperfect number, because it is the sum of a subset of its proper divisors.

120130000000002 is a wasteful number, since it uses less digits than its factorization.

120130000000002 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 6673888888897 (or 6673888888894 counting only the distinct ones).

The product of its (nonzero) digits is 12, while the sum is 9.

Adding to 120130000000002 its reverse (200000000031021), we get a palindrome (320130000031023).

The spelling of 120130000000002 in words is "one hundred twenty trillion, one hundred thirty billion, two", and thus it is an aban number.

Divisors: 1 2 3 6 9 18 6673888888889 13347777777778 20021666666667 40043333333334 60065000000001 120130000000002