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120131000000 = 26561167163
BaseRepresentation
bin110111111100001011…
…1011001011011000000
3102111002010200002201022
41233320113121123000
53432012014000000
6131104252125012
711451646436414
oct1577027313300
9374063602638
10120131000000
1146a468aa390
121b347766768
13b43639306b
145b588c6d44
1531d1730585
hex1bf85d96c0

120131000000 has 392 divisors, whose sum is σ = 331942001088. Its totient is φ = 42768000000.

The previous prime is 120130999991. The next prime is 120131000027. The reversal of 120131000000 is 131021.

It is a super-2 number, since 2×1201310000002 (a number of 23 digits) contains 22 as substring.

It is a Harshad number since it is a multiple of its sum of digits (8).

It is an unprimeable number.

It is a polite number, since it can be written in 55 ways as a sum of consecutive naturals, for example, 736999919 + ... + 737000081.

Almost surely, 2120131000000 is an apocalyptic number.

120131000000 is a gapful number since it is divisible by the number (10) formed by its first and last digit.

It is an amenable number.

It is a practical number, because each smaller number is the sum of distinct divisors of 120131000000, and also a Zumkeller number, because its divisors can be partitioned in two sets with the same sum (165971000544).

120131000000 is an abundant number, since it is smaller than the sum of its proper divisors (211811001088).

It is a pseudoperfect number, because it is the sum of a subset of its proper divisors.

120131000000 is an frugal number, since it uses more digits than its factorization.

120131000000 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 283 (or 248 counting only the distinct ones).

The product of its (nonzero) digits is 6, while the sum is 8.

Adding to 120131000000 its reverse (131021), we get a palindrome (120131131021).

The spelling of 120131000000 in words is "one hundred twenty billion, one hundred thirty-one million", and thus it is an aban number.