Base | Representation |
---|---|
bin | 11011010100001000111010… |
… | …001010001101001100011101 |
3 | 120202100102122122110121222220 |
4 | 123110020322022031030131 |
5 | 111221212210010220013 |
6 | 1103255303320255553 |
7 | 34206123253400202 |
oct | 3324107212151435 |
9 | 522312578417886 |
10 | 120131211023133 |
11 | 353063a6898a02 |
12 | 115822976115b9 |
13 | 520542b18512b |
14 | 219454b2d7ca9 |
15 | dd4d4d980b23 |
hex | 6d423a28d31d |
120131211023133 has 32 divisors (see below), whose sum is σ = 171130326551040. Its totient is φ = 74736154785600.
The previous prime is 120131211023099. The next prime is 120131211023149. The reversal of 120131211023133 is 331320112131021.
It is not a de Polignac number, because 120131211023133 - 217 = 120131210892061 is a prime.
It is a super-2 number, since 2×1201312110231332 (a number of 29 digits) contains 22 as substring.
It is a congruent number.
It is not an unprimeable number, because it can be changed into a prime (120131211023183) by changing a digit.
It is a polite number, since it can be written in 31 ways as a sum of consecutive naturals, for example, 75983266 + ... + 77548172.
It is an arithmetic number, because the mean of its divisors is an integer number (5347822704720).
Almost surely, 2120131211023133 is an apocalyptic number.
It is an amenable number.
120131211023133 is a deficient number, since it is larger than the sum of its proper divisors (50999115527907).
120131211023133 is a wasteful number, since it uses less digits than its factorization.
120131211023133 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 1585097.
The product of its (nonzero) digits is 648, while the sum is 24.
Adding to 120131211023133 its reverse (331320112131021), we get a palindrome (451451323154154).
The spelling of 120131211023133 in words is "one hundred twenty trillion, one hundred thirty-one billion, two hundred eleven million, twenty-three thousand, one hundred thirty-three".
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