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1201324543 is a prime number
BaseRepresentation
bin100011110011010…
…1100000111111111
310002201111121110121
41013212230013333
54430014341133
6315112315411
741525042626
oct10746540777
93081447417
101201324543
11567130a01
122963a2b67
13161b69333
14b57966bd
15706ed02d
hex479ac1ff

1201324543 has 2 divisors, whose sum is σ = 1201324544. Its totient is φ = 1201324542.

The previous prime is 1201324519. The next prime is 1201324549. The reversal of 1201324543 is 3454231021.

It is a strong prime.

It is a cyclic number.

It is not a de Polignac number, because 1201324543 - 25 = 1201324511 is a prime.

It is a super-2 number, since 2×12013245432 = 2886361315228317698, which contains 22 as substring.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (1201324549) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (19) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 600662271 + 600662272.

It is an arithmetic number, because the mean of its divisors is an integer number (600662272).

Almost surely, 21201324543 is an apocalyptic number.

1201324543 is a deficient number, since it is larger than the sum of its proper divisors (1).

1201324543 is an equidigital number, since it uses as much as digits as its factorization.

1201324543 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 2880, while the sum is 25.

The square root of 1201324543 is about 34660.1290101465. The cubic root of 1201324543 is about 1063.0494079086.

Adding to 1201324543 its reverse (3454231021), we get a palindrome (4655555564).

The spelling of 1201324543 in words is "one billion, two hundred one million, three hundred twenty-four thousand, five hundred forty-three".