Base | Representation |
---|---|
bin | 100011110011011… |
… | …0000101101010101 |
3 | 10002201112120012221 |
4 | 1013212300231111 |
5 | 4430020441232 |
6 | 315112542341 |
7 | 41525151436 |
oct | 10746605525 |
9 | 3081476187 |
10 | 1201343317 |
11 | 567144019 |
12 | 2963b19b1 |
13 | 161b74a45 |
14 | b579d48d |
15 | 70703897 |
hex | 479b0b55 |
1201343317 has 2 divisors, whose sum is σ = 1201343318. Its totient is φ = 1201343316.
The previous prime is 1201343303. The next prime is 1201343321. The reversal of 1201343317 is 7133431021.
It is a strong prime.
It can be written as a sum of positive squares in only one way, i.e., 1200345316 + 998001 = 34646^2 + 999^2 .
It is a cyclic number.
It is a de Polignac number, because none of the positive numbers 2k-1201343317 is a prime.
It is a junction number, because it is equal to n+sod(n) for n = 1201343291 and 1201343300.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (1201343387) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 600671658 + 600671659.
It is an arithmetic number, because the mean of its divisors is an integer number (600671659).
Almost surely, 21201343317 is an apocalyptic number.
It is an amenable number.
1201343317 is a deficient number, since it is larger than the sum of its proper divisors (1).
1201343317 is an equidigital number, since it uses as much as digits as its factorization.
1201343317 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 1512, while the sum is 25.
The square root of 1201343317 is about 34660.3998390094. The cubic root of 1201343317 is about 1063.0549455700.
Adding to 1201343317 its reverse (7133431021), we get a palindrome (8334774338).
The spelling of 1201343317 in words is "one billion, two hundred one million, three hundred forty-three thousand, three hundred seventeen".
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