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120203143133 is a prime number
BaseRepresentation
bin110111111110010101…
…0100110011111011101
3102111021011102100111012
41233330222212133131
53432134001040013
6131115350305005
711453513600303
oct1577452463735
9374234370435
10120203143133
1146a835a4607
121b367958165
13b4483021c8
145b64306273
1531d7c311a8
hex1bfcaa67dd

120203143133 has 2 divisors, whose sum is σ = 120203143134. Its totient is φ = 120203143132.

The previous prime is 120203143097. The next prime is 120203143147. The reversal of 120203143133 is 331341302021.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 100528311844 + 19674831289 = 317062^2 + 140267^2 .

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2k-120203143133 is a prime.

It is a junction number, because it is equal to n+sod(n) for n = 120203143099 and 120203143108.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (120203143153) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 60101571566 + 60101571567.

It is an arithmetic number, because the mean of its divisors is an integer number (60101571567).

Almost surely, 2120203143133 is an apocalyptic number.

It is an amenable number.

120203143133 is a deficient number, since it is larger than the sum of its proper divisors (1).

120203143133 is an equidigital number, since it uses as much as digits as its factorization.

120203143133 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 1296, while the sum is 23.

Adding to 120203143133 its reverse (331341302021), we get a palindrome (451544445154).

The spelling of 120203143133 in words is "one hundred twenty billion, two hundred three million, one hundred forty-three thousand, one hundred thirty-three".