Base | Representation |
---|---|
bin | 100011110100111… |
… | …0001100001111001 |
3 | 10002210000200121122 |
4 | 1013221301201321 |
5 | 4430221224423 |
6 | 315141515025 |
7 | 41534651156 |
oct | 10751614171 |
9 | 3083020548 |
10 | 1202133113 |
11 | 567633445 |
12 | 296712a75 |
13 | 16209038c |
14 | b592722d |
15 | 7080c8c8 |
hex | 47a71879 |
1202133113 has 2 divisors, whose sum is σ = 1202133114. Its totient is φ = 1202133112.
The previous prime is 1202133103. The next prime is 1202133131. The reversal of 1202133113 is 3113312021.
Together with next prime (1202133131) it forms an Ormiston pair, because they use the same digits, order apart.
It is a weak prime.
It can be written as a sum of positive squares in only one way, i.e., 811794064 + 390339049 = 28492^2 + 19757^2 .
It is a cyclic number.
It is not a de Polignac number, because 1202133113 - 28 = 1202132857 is a prime.
It is a junction number, because it is equal to n+sod(n) for n = 1202133091 and 1202133100.
It is not a weakly prime, because it can be changed into another prime (1202133103) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 601066556 + 601066557.
It is an arithmetic number, because the mean of its divisors is an integer number (601066557).
Almost surely, 21202133113 is an apocalyptic number.
It is an amenable number.
1202133113 is a deficient number, since it is larger than the sum of its proper divisors (1).
1202133113 is an equidigital number, since it uses as much as digits as its factorization.
1202133113 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 108, while the sum is 17.
The square root of 1202133113 is about 34671.7913151311. The cubic root of 1202133113 is about 1063.2878550161.
Adding to 1202133113 its reverse (3113312021), we get a palindrome (4315445134).
The spelling of 1202133113 in words is "one billion, two hundred two million, one hundred thirty-three thousand, one hundred thirteen".
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