Base | Representation |
---|---|
bin | 1010111011110010001110… |
… | …1100000011011000011011 |
3 | 1120120022102122021101202021 |
4 | 2232330203230003120123 |
5 | 3033432442311243001 |
6 | 41322532242515311 |
7 | 2350401424500553 |
oct | 256744354033033 |
9 | 46508378241667 |
10 | 12022212212251 |
11 | 391565641470a |
12 | 1421b9a665b37 |
13 | 6928c74b3647 |
14 | 2d7c41a00163 |
15 | 15cad2ebbba1 |
hex | aef23b0361b |
12022212212251 has 2 divisors, whose sum is σ = 12022212212252. Its totient is φ = 12022212212250.
The previous prime is 12022212212207. The next prime is 12022212212267. The reversal of 12022212212251 is 15221221222021.
It is a strong prime.
It is an emirp because it is prime and its reverse (15221221222021) is a distict prime.
It is a cyclic number.
It is not a de Polignac number, because 12022212212251 - 233 = 12013622277659 is a prime.
It is not a weakly prime, because it can be changed into another prime (12022212212281) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (23) of ones.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 6011106106125 + 6011106106126.
It is an arithmetic number, because the mean of its divisors is an integer number (6011106106126).
Almost surely, 212022212212251 is an apocalyptic number.
12022212212251 is a deficient number, since it is larger than the sum of its proper divisors (1).
12022212212251 is an equidigital number, since it uses as much as digits as its factorization.
12022212212251 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 1280, while the sum is 25.
Adding to 12022212212251 its reverse (15221221222021), we get a palindrome (27243433434272).
The spelling of 12022212212251 in words is "twelve trillion, twenty-two billion, two hundred twelve million, two hundred twelve thousand, two hundred fifty-one".
• e-mail: info -at- numbersaplenty.com • Privacy notice • done in 0.069 sec. • engine limits •