120245113132141 has 4 divisors (see below), whose sum is σ = 120849359932000. Its totient is φ = 119640866332284.

The previous prime is 120245113132087. The next prime is 120245113132279. The reversal of 120245113132141 is 141231311542021.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.

It is a cyclic number.

It is not a de Polignac number, because 120245113132141 - 2⁷ = 120245113132013 is a prime.

It is a super-2 number, since 2×120245113132141² (a number of 29 digits) contains 22 as substring.

It is a Duffinian number.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (120245113130141) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 302123399631 + ... + 302123400028.

It is an arithmetic number, because the mean of its divisors is an integer number (30212339983000).

Almost surely, 2^{120245113132141} is an apocalyptic number.

It is an amenable number.

120245113132141 is a deficient number, since it is larger than the sum of its proper divisors (604246799859).

120245113132141 is an equidigital number, since it uses as much as digits as its factorization.

120245113132141 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 604246799858.

The product of its (nonzero) digits is 5760, while the sum is 31.

Adding to 120245113132141 its reverse (141231311542021), we get a palindrome (261476424674162).

The spelling of 120245113132141 in words is "one hundred twenty trillion, two hundred forty-five billion, one hundred thirteen million, one hundred thirty-two thousand, one hundred forty-one".