Base | Representation |
---|---|
bin | 1010111101000000110111… |
… | …1000000101100000110011 |
3 | 1120122022220202101020002220 |
4 | 2233100031320011200303 |
5 | 3034304210200320220 |
6 | 41340343023412123 |
7 | 2352046503224355 |
oct | 257201570054063 |
9 | 46568822336086 |
10 | 12043321104435 |
11 | 39235a8881855 |
12 | 14260aba54043 |
13 | 6948ac8334aa |
14 | 2d8c8529b0d5 |
15 | 15d41b278540 |
hex | af40de05833 |
12043321104435 has 16 divisors (see below), whose sum is σ = 19269497103360. Its totient is φ = 6423043476960.
The previous prime is 12043321104433. The next prime is 12043321104469. The reversal of 12043321104435 is 53440112334021.
It is not a de Polignac number, because 12043321104435 - 21 = 12043321104433 is a prime.
It is a junction number, because it is equal to n+sod(n) for n = 12043321104396 and 12043321104405.
It is not an unprimeable number, because it can be changed into a prime (12043321104433) by changing a digit.
It is a polite number, since it can be written in 15 ways as a sum of consecutive naturals, for example, 2167345 + ... + 5365074.
It is an arithmetic number, because the mean of its divisors is an integer number (1204343568960).
Almost surely, 212043321104435 is an apocalyptic number.
12043321104435 is a gapful number since it is divisible by the number (15) formed by its first and last digit.
12043321104435 is a deficient number, since it is larger than the sum of its proper divisors (7226175998925).
12043321104435 is a wasteful number, since it uses less digits than its factorization.
12043321104435 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 7639018.
The product of its (nonzero) digits is 34560, while the sum is 33.
Adding to 12043321104435 its reverse (53440112334021), we get a palindrome (65483433438456).
The spelling of 12043321104435 in words is "twelve trillion, forty-three billion, three hundred twenty-one million, one hundred four thousand, four hundred thirty-five".
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