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12049313 is a prime number
BaseRepresentation
bin101101111101…
…101110100001
3211200011112212
4231331232201
511041034223
61110131505
7204263123
oct55755641
924604485
1012049313
11688a911
124050b95
13265b593
141859213
1510d0278
hexb7dba1

12049313 has 2 divisors, whose sum is σ = 12049314. Its totient is φ = 12049312.

The previous prime is 12049273. The next prime is 12049319. The reversal of 12049313 is 31394021.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 6512704 + 5536609 = 2552^2 + 2353^2 .

It is an emirp because it is prime and its reverse (31394021) is a distict prime.

It is a cyclic number.

It is not a de Polignac number, because 12049313 - 212 = 12045217 is a prime.

It is a Chen prime.

It is not a weakly prime, because it can be changed into another prime (12049319) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 6024656 + 6024657.

It is an arithmetic number, because the mean of its divisors is an integer number (6024657).

Almost surely, 212049313 is an apocalyptic number.

It is an amenable number.

12049313 is a deficient number, since it is larger than the sum of its proper divisors (1).

12049313 is an equidigital number, since it uses as much as digits as its factorization.

12049313 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 648, while the sum is 23.

The square root of 12049313 is about 3471.2120361626. The cubic root of 12049313 is about 229.2560270937.

The spelling of 12049313 in words is "twelve million, forty-nine thousand, three hundred thirteen".