Base | Representation |
---|---|
bin | 10110100010101011… |
… | …00110001011011101 |
3 | 1011020102010000212201 |
4 | 23101111212023131 |
5 | 144241110043031 |
6 | 5320512331501 |
7 | 605620410241 |
oct | 132125461335 |
9 | 34212100781 |
10 | 12102034141 |
11 | 515031240a |
12 | 2418b43b91 |
13 | 11ab33b162 |
14 | 82b3bc421 |
15 | 4ac6c7d61 |
hex | 2d15662dd |
12102034141 has 2 divisors, whose sum is σ = 12102034142. Its totient is φ = 12102034140.
The previous prime is 12102034121. The next prime is 12102034163. The reversal of 12102034141 is 14143020121.
It is a weak prime.
It can be written as a sum of positive squares in only one way, i.e., 11920054041 + 181980100 = 109179^2 + 13490^2 .
It is a cyclic number.
It is not a de Polignac number, because 12102034141 - 211 = 12102032093 is a prime.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (12102034121) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 6051017070 + 6051017071.
It is an arithmetic number, because the mean of its divisors is an integer number (6051017071).
Almost surely, 212102034141 is an apocalyptic number.
It is an amenable number.
12102034141 is a deficient number, since it is larger than the sum of its proper divisors (1).
12102034141 is an equidigital number, since it uses as much as digits as its factorization.
12102034141 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 192, while the sum is 19.
Adding to 12102034141 its reverse (14143020121), we get a palindrome (26245054262).
The spelling of 12102034141 in words is "twelve billion, one hundred two million, thirty-four thousand, one hundred forty-one".
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