1211001099947 has 2 divisors, whose sum is σ = 1211001099948. Its totient is φ = 1211001099946.

The previous prime is 1211001099929. The next prime is 1211001099949. The reversal of 1211001099947 is 7499901001121.

It is a strong prime.

It is a cyclic number.

It is not a de Polignac number, because 1211001099947 - 2⁶ = 1211001099883 is a prime.

Together with 1211001099949, it forms a pair of twin primes.

It is a Chen prime.

It is a junction number, because it is equal to n+sod(n) for n = 1211001099898 and 1211001099907.

It is not a weakly prime, because it can be changed into another prime (1211001099949) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 605500549973 + 605500549974.

It is an arithmetic number, because the mean of its divisors is an integer number (605500549974).

Almost surely, 2^{1211001099947} is an apocalyptic number.

1211001099947 is a deficient number, since it is larger than the sum of its proper divisors (1).

1211001099947 is an equidigital number, since it uses as much as digits as its factorization.

1211001099947 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 40824, while the sum is 44.

The spelling of 1211001099947 in words is "one trillion, two hundred eleven billion, one million, ninety-nine thousand, nine hundred forty-seven".