Base | Representation |
---|---|
bin | 1011000001000100110100… |
… | …0101101011101101011110 |
3 | 1120220000000211202210111112 |
4 | 2300101031011223231132 |
5 | 3041430112341010420 |
6 | 41432403135222022 |
7 | 2360066636413220 |
oct | 260211505535536 |
9 | 46800024683445 |
10 | 12113101110110 |
11 | 3950156874930 |
12 | 1437725077912 |
13 | 69b350512b90 |
14 | 2dc3c49a8410 |
15 | 1601523d08c5 |
hex | b044d16bb5e |
12113101110110 has 128 divisors (see below), whose sum is σ = 29304912043008. Its totient is φ = 3481496064000.
The previous prime is 12113101110101. The next prime is 12113101110113. The reversal of 12113101110110 is 1101110131121.
12113101110110 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.
It is a super-2 number, since 2×121131011101102 (a number of 27 digits) contains 22 as substring.
It is a Harshad number since it is a multiple of its sum of digits (14).
It is a congruent number.
It is not an unprimeable number, because it can be changed into a prime (12113101110113) by changing a digit.
It is a polite number, since it can be written in 63 ways as a sum of consecutive naturals, for example, 9096590 + ... + 10342830.
It is an arithmetic number, because the mean of its divisors is an integer number (228944625336).
Almost surely, 212113101110110 is an apocalyptic number.
12113101110110 is a gapful number since it is divisible by the number (10) formed by its first and last digit.
12113101110110 is an abundant number, since it is smaller than the sum of its proper divisors (17191810932898).
It is a pseudoperfect number, because it is the sum of a subset of its proper divisors.
12113101110110 is a wasteful number, since it uses less digits than its factorization.
12113101110110 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 1247250.
The product of its (nonzero) digits is 6, while the sum is 14.
Adding to 12113101110110 its reverse (1101110131121), we get a palindrome (13214211241231).
It can be divided in two parts, 121131011 and 10110, that added together give a palindrome (121141121).
The spelling of 12113101110110 in words is "twelve trillion, one hundred thirteen billion, one hundred one million, one hundred ten thousand, one hundred ten".
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