12113113 has 4 divisors (see below), whose sum is σ = 12318480. Its totient is φ = 11907748.

The previous prime is 12113093. The next prime is 12113117. The reversal of 12113113 is 31131121.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.

It is a cyclic number.

It is not a de Polignac number, because 12113113 - 2¹⁷ = 11982041 is a prime.

It is a Duffinian number.

It is a junction number, because it is equal to n+sod(n) for n = 12113093 and 12113102.

It is not an unprimeable number, because it can be changed into a prime (12113117) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (13) of ones.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 102595 + ... + 102712.

It is an arithmetic number, because the mean of its divisors is an integer number (3079620).

Almost surely, 2^12113113 is an apocalyptic number.

It is an amenable number.

12113113 is a deficient number, since it is larger than the sum of its proper divisors (205367).

12113113 is an equidigital number, since it uses as much as digits as its factorization.

12113113 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 205366.

The product of its digits is 18, while the sum is 13.

The square root of 12113113 is about 3480.3897770221. The cubic root of 12113113 is about 229.6599448611.

Adding to 12113113 its reverse (31131121), we get a palindrome (43244234).

The spelling of 12113113 in words is "twelve million, one hundred thirteen thousand, one hundred thirteen".