Base | Representation |
---|---|
bin | 111000011100011001… |
… | …1100000110010110011 |
3 | 102120212110222021122101 |
4 | 1300320303200302303 |
5 | 3441220300041201 |
6 | 131403432121231 |
7 | 11520514644532 |
oct | 1607063406263 |
9 | 376773867571 |
10 | 121212112051 |
11 | 47451093918 |
12 | 1b5a9836217 |
13 | b57935c834 |
14 | 5c1c30a319 |
15 | 32465d4d01 |
hex | 1c38ce0cb3 |
121212112051 has 2 divisors, whose sum is σ = 121212112052. Its totient is φ = 121212112050.
The previous prime is 121212112019. The next prime is 121212112079. The reversal of 121212112051 is 150211212121.
It is a strong prime.
It is a cyclic number.
It is not a de Polignac number, because 121212112051 - 25 = 121212112019 is a prime.
It is a super-2 number, since 2×1212121120512 (a number of 23 digits) contains 22 as substring.
It is not a weakly prime, because it can be changed into another prime (121212112001) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 60606056025 + 60606056026.
It is an arithmetic number, because the mean of its divisors is an integer number (60606056026).
Almost surely, 2121212112051 is an apocalyptic number.
121212112051 is a deficient number, since it is larger than the sum of its proper divisors (1).
121212112051 is an equidigital number, since it uses as much as digits as its factorization.
121212112051 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 80, while the sum is 19.
Adding to 121212112051 its reverse (150211212121), we get a palindrome (271423324172).
The spelling of 121212112051 in words is "one hundred twenty-one billion, two hundred twelve million, one hundred twelve thousand, fifty-one".
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