Base | Representation |
---|---|
bin | 111000100000010011… |
… | …1111111100101011001 |
3 | 102121012121211211121221 |
4 | 1301000213333211121 |
5 | 3442002341411134 |
6 | 131424440132041 |
7 | 11524000055404 |
oct | 1610047774531 |
9 | 377177754557 |
10 | 121343310169 |
11 | 47509153a14 |
12 | 1b625767021 |
13 | b59a5a7763 |
14 | 5c318dcd3b |
15 | 3252d9d5b4 |
hex | 1c409ff959 |
121343310169 has 2 divisors, whose sum is σ = 121343310170. Its totient is φ = 121343310168.
The previous prime is 121343310161. The next prime is 121343310227. The reversal of 121343310169 is 961013343121.
It is a weak prime.
It can be written as a sum of positive squares in only one way, i.e., 92667274569 + 28676035600 = 304413^2 + 169340^2 .
It is a cyclic number.
It is not a de Polignac number, because 121343310169 - 23 = 121343310161 is a prime.
It is a super-2 number, since 2×1213433101692 (a number of 23 digits) contains 22 as substring.
It is not a weakly prime, because it can be changed into another prime (121343310161) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 60671655084 + 60671655085.
It is an arithmetic number, because the mean of its divisors is an integer number (60671655085).
Almost surely, 2121343310169 is an apocalyptic number.
It is an amenable number.
121343310169 is a deficient number, since it is larger than the sum of its proper divisors (1).
121343310169 is an equidigital number, since it uses as much as digits as its factorization.
121343310169 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 11664, while the sum is 34.
The spelling of 121343310169 in words is "one hundred twenty-one billion, three hundred forty-three million, three hundred ten thousand, one hundred sixty-nine".
• e-mail: info -at- numbersaplenty.com • Privacy notice • done in 0.074 sec. • engine limits •