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BaseRepresentation
bin10001101010000110001…
…111111011111011011001
311022000002020110101202021
4101222012033323323121
5124340102333231131
62325235442334441
7153445001120566
oct21520617737331
94260066411667
101213433102041
11428683396516
1217720835a421
138a57061abb4
1442a325d386d
152186e18de11
hex11a863fbed9

1213433102041 has 4 divisors (see below), whose sum is σ = 1230523709184. Its totient is φ = 1196342494900.

The previous prime is 1213433102023. The next prime is 1213433102087. The reversal of 1213433102041 is 1402013343121.

Adding to 1213433102041 its reverse (1402013343121), we get a palindrome (2615446445162).

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.

It is a cyclic number.

It is not a de Polignac number, because 1213433102041 - 213 = 1213433093849 is a prime.

It is a Duffinian number.

It is a junction number, because it is equal to n+sod(n) for n = 1213433101997 and 1213433102015.

It is not an unprimeable number, because it can be changed into a prime (1213433102741) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 8545303465 + ... + 8545303606.

It is an arithmetic number, because the mean of its divisors is an integer number (307630927296).

Almost surely, 21213433102041 is an apocalyptic number.

It is an amenable number.

1213433102041 is a deficient number, since it is larger than the sum of its proper divisors (17090607143).

1213433102041 is an equidigital number, since it uses as much as digits as its factorization.

1213433102041 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 17090607142.

The product of its (nonzero) digits is 1728, while the sum is 25.

The spelling of 1213433102041 in words is "one trillion, two hundred thirteen billion, four hundred thirty-three million, one hundred two thousand, forty-one".

Divisors: 1 71 17090607071 1213433102041