Base | Representation |
---|---|
bin | 10110101110011110… |
… | …01000010010000001 |
3 | 1011111022100010102011 |
4 | 23113033020102001 |
5 | 144441424031423 |
6 | 5334405452521 |
7 | 611231543506 |
oct | 132717102201 |
9 | 34438303364 |
10 | 12201002113 |
11 | 51a1169523 |
12 | 2446111141 |
13 | 11c59acca1 |
14 | 83a5c14ad |
15 | 4b6226b0d |
hex | 2d73c8481 |
12201002113 has 2 divisors, whose sum is σ = 12201002114. Its totient is φ = 12201002112.
The previous prime is 12201002087. The next prime is 12201002123. The reversal of 12201002113 is 31120010221.
It is a strong prime.
It can be written as a sum of positive squares in only one way, i.e., 11917652224 + 283349889 = 109168^2 + 16833^2 .
It is a cyclic number.
It is a de Polignac number, because none of the positive numbers 2k-12201002113 is a prime.
It is a super-2 number, since 2×122010021132 (a number of 21 digits) contains 22 as substring.
It is a junction number, because it is equal to n+sod(n) for n = 12201002093 and 12201002102.
It is not a weakly prime, because it can be changed into another prime (12201002123) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 6100501056 + 6100501057.
It is an arithmetic number, because the mean of its divisors is an integer number (6100501057).
Almost surely, 212201002113 is an apocalyptic number.
It is an amenable number.
12201002113 is a deficient number, since it is larger than the sum of its proper divisors (1).
12201002113 is an equidigital number, since it uses as much as digits as its factorization.
12201002113 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 24, while the sum is 13.
Adding to 12201002113 its reverse (31120010221), we get a palindrome (43321012334).
The spelling of 12201002113 in words is "twelve billion, two hundred one million, two thousand, one hundred thirteen".
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