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122113100120130 = 232576118111754581
BaseRepresentation
bin11011110000111110101011…
…111101001000000001000010
3121000100220020220110021121200
4123300332223331020001002
5112001200112112321010
61111413552254002030
734502244312640620
oct3360765375100102
9530326226407550
10122113100120130
11359aa969599259
12118424061a6316
13531a2a6528842
14222243c72c510
15e1b696999cc0
hex6f0fabf48042

122113100120130 has 192 divisors, whose sum is σ = 369002575109376. Its totient is φ = 27438823872000.

The previous prime is 122113100120129. The next prime is 122113100120147. The reversal of 122113100120130 is 31021001311221.

122113100120130 is a `hidden beast` number, since 1 + 2 + 211 + 310 + 0 + 12 + 0 + 130 = 666.

It is a Harshad number since it is a multiple of its sum of digits (18).

It is an unprimeable number.

It is a pernicious number, because its binary representation contains a prime number (23) of ones.

It is a polite number, since it can be written in 95 ways as a sum of consecutive naturals, for example, 68719440 + ... + 70474020.

It is an arithmetic number, because the mean of its divisors is an integer number (1921888412028).

Almost surely, 2122113100120130 is an apocalyptic number.

122113100120130 is a gapful number since it is divisible by the number (10) formed by its first and last digit.

It is a practical number, because each smaller number is the sum of distinct divisors of 122113100120130, and also a Zumkeller number, because its divisors can be partitioned in two sets with the same sum (184501287554688).

122113100120130 is an abundant number, since it is smaller than the sum of its proper divisors (246889474989246).

It is a pseudoperfect number, because it is the sum of a subset of its proper divisors.

122113100120130 is a wasteful number, since it uses less digits than its factorization.

122113100120130 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 1756473 (or 1756470 counting only the distinct ones).

The product of its (nonzero) digits is 72, while the sum is 18.

Adding to 122113100120130 its reverse (31021001311221), we get a palindrome (153134101431351).

The spelling of 122113100120130 in words is "one hundred twenty-two trillion, one hundred thirteen billion, one hundred million, one hundred twenty thousand, one hundred thirty".