Base | Representation |
---|---|
bin | 1011001101001000101101… |
… | …0011010111000001101001 |
3 | 1121121210212010021022000011 |
4 | 2303102023103113001221 |
5 | 3103323440122004001 |
6 | 42111511425411521 |
7 | 2411053413160255 |
oct | 263221323270151 |
9 | 47553763238004 |
10 | 12320303313001 |
11 | 3a20014037722 |
12 | 146b910799ba1 |
13 | 6b4a519b3b68 |
14 | 30843d3dd265 |
15 | 16572ccb0d51 |
hex | b348b4d7069 |
12320303313001 has 2 divisors, whose sum is σ = 12320303313002. Its totient is φ = 12320303313000.
The previous prime is 12320303312939. The next prime is 12320303313013. The reversal of 12320303313001 is 10031330302321.
It is a strong prime.
It can be written as a sum of positive squares in only one way, i.e., 12177838584976 + 142464728025 = 3489676^2 + 377445^2 .
It is a cyclic number.
It is a de Polignac number, because none of the positive numbers 2k-12320303313001 is a prime.
It is not a weakly prime, because it can be changed into another prime (12320303313041) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 6160151656500 + 6160151656501.
It is an arithmetic number, because the mean of its divisors is an integer number (6160151656501).
Almost surely, 212320303313001 is an apocalyptic number.
It is an amenable number.
12320303313001 is a deficient number, since it is larger than the sum of its proper divisors (1).
12320303313001 is an equidigital number, since it uses as much as digits as its factorization.
12320303313001 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 972, while the sum is 22.
Adding to 12320303313001 its reverse (10031330302321), we get a palindrome (22351633615322).
The spelling of 12320303313001 in words is "twelve trillion, three hundred twenty billion, three hundred three million, three hundred thirteen thousand, one".
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