Base | Representation |
---|---|
bin | 11100000010010010001001… |
… | …110000110100110000000110 |
3 | 121011120120121120122120111211 |
4 | 130002102021300310300012 |
5 | 112130140432444124032 |
6 | 1114124132533522034 |
7 | 34654202156433121 |
oct | 3402221160646006 |
9 | 534516546576454 |
10 | 123302232411142 |
11 | 36319201793774 |
12 | 119b49701a331a |
13 | 53a54734273c5 |
14 | 2263c077813b8 |
15 | e3c592528747 |
hex | 702489c34c06 |
123302232411142 has 4 divisors (see below), whose sum is σ = 184953348616716. Its totient is φ = 61651116205570.
The previous prime is 123302232411139. The next prime is 123302232411217. The reversal of 123302232411142 is 241114232203321.
It is a semiprime because it is the product of two primes.
It is a congruent number.
It is an unprimeable number.
It is a pernicious number, because its binary representation contains a prime number (17) of ones.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 30825558102784 + ... + 30825558102787.
It is an arithmetic number, because the mean of its divisors is an integer number (46238337154179).
Almost surely, 2123302232411142 is an apocalyptic number.
123302232411142 is a deficient number, since it is larger than the sum of its proper divisors (61651116205574).
123302232411142 is an equidigital number, since it uses as much as digits as its factorization.
123302232411142 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 61651116205573.
The product of its (nonzero) digits is 13824, while the sum is 31.
Adding to 123302232411142 its reverse (241114232203321), we get a palindrome (364416464614463).
The spelling of 123302232411142 in words is "one hundred twenty-three trillion, three hundred two billion, two hundred thirty-two million, four hundred eleven thousand, one hundred forty-two".
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