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123311212113 = 341103737371
BaseRepresentation
bin111001011010111101…
…0111100011001010001
3102210021202210121121010
41302311322330121101
54010020132241423
6132352015121133
711623524003015
oct1626572743121
9383252717533
10123311212113
1148328a67861
121ba948131a9
13b8221c3b8b
145d7b000545
15331aa20693
hex1cb5ebc651

123311212113 has 4 divisors (see below), whose sum is σ = 164414949488. Its totient is φ = 82207474740.

The previous prime is 123311212111. The next prime is 123311212139. The reversal of 123311212113 is 311212113321.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.

It is not a de Polignac number, because 123311212113 - 21 = 123311212111 is a prime.

It is a Duffinian number.

It is a self number, because there is not a number n which added to its sum of digits gives 123311212113.

It is not an unprimeable number, because it can be changed into a prime (123311212111) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 20551868683 + ... + 20551868688.

It is an arithmetic number, because the mean of its divisors is an integer number (41103737372).

Almost surely, 2123311212113 is an apocalyptic number.

It is an amenable number.

123311212113 is a deficient number, since it is larger than the sum of its proper divisors (41103737375).

123311212113 is an equidigital number, since it uses as much as digits as its factorization.

123311212113 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 41103737374.

The product of its digits is 216, while the sum is 21.

Adding to 123311212113 its reverse (311212113321), we get a palindrome (434523325434).

The spelling of 123311212113 in words is "one hundred twenty-three billion, three hundred eleven million, two hundred twelve thousand, one hundred thirteen".

Divisors: 1 3 41103737371 123311212113