123314343436657 has 2 divisors, whose sum is σ = 123314343436658. Its totient is φ = 123314343436656.

The previous prime is 123314343436643. The next prime is 123314343436667. The reversal of 123314343436657 is 756634343413321.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 121449414527281 + 1864928909376 = 11020409^2 + 1365624^2 .

It is a cyclic number.

It is not a de Polignac number, because 123314343436657 - 2¹¹ = 123314343434609 is a prime.

It is a junction number, because it is equal to n+sod(n) for n = 123314343436598 and 123314343436607.

It is not a weakly prime, because it can be changed into another prime (123314343436667) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (23) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 61657171718328 + 61657171718329.

It is an arithmetic number, because the mean of its divisors is an integer number (61657171718329).

Almost surely, 2^{123314343436657} is an apocalyptic number.

It is an amenable number.

123314343436657 is a deficient number, since it is larger than the sum of its proper divisors (1).

123314343436657 is an equidigital number, since it uses as much as digits as its factorization.

123314343436657 is an odious number, because the sum of its binary digits is odd.

The product of its digits is 39191040, while the sum is 55.

Adding to 123314343436657 its reverse (756634343413321), we get a palindrome (879948686849978).

The spelling of 123314343436657 in words is "one hundred twenty-three trillion, three hundred fourteen billion, three hundred forty-three million, four hundred thirty-six thousand, six hundred fifty-seven".