Base | Representation |
---|---|
bin | 11100000100000010111111… |
… | …111011101001111000000011 |
3 | 121012000011100222102022000011 |
4 | 130010002333323221320003 |
5 | 112134132110434213011 |
6 | 1114255532150205351 |
7 | 34666021626511264 |
oct | 3404027773517003 |
9 | 535004328368004 |
10 | 123423400304131 |
11 | 3636562a915104 |
12 | 11a14347053857 |
13 | 53b3a13573bc5 |
14 | 2269a1dc5a96b |
15 | e407d4cc6621 |
hex | 7040bfee9e03 |
123423400304131 has 2 divisors, whose sum is σ = 123423400304132. Its totient is φ = 123423400304130.
The previous prime is 123423400304117. The next prime is 123423400304143. The reversal of 123423400304131 is 131403004324321.
It is a strong prime.
It is a cyclic number.
It is not a de Polignac number, because 123423400304131 - 225 = 123423366749699 is a prime.
It is a super-2 number, since 2×1234234003041312 (a number of 29 digits) contains 22 as substring.
It is a junction number, because it is equal to n+sod(n) for n = 123423400304093 and 123423400304102.
It is not a weakly prime, because it can be changed into another prime (123423400305131) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 61711700152065 + 61711700152066.
It is an arithmetic number, because the mean of its divisors is an integer number (61711700152066).
Almost surely, 2123423400304131 is an apocalyptic number.
123423400304131 is a deficient number, since it is larger than the sum of its proper divisors (1).
123423400304131 is an equidigital number, since it uses as much as digits as its factorization.
123423400304131 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 20736, while the sum is 31.
Adding to 123423400304131 its reverse (131403004324321), we get a palindrome (254826404628452).
The spelling of 123423400304131 in words is "one hundred twenty-three trillion, four hundred twenty-three billion, four hundred million, three hundred four thousand, one hundred thirty-one".
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