Base | Representation |
---|---|
bin | 11100001100111000111001… |
… | …000101100110100110101111 |
3 | 121021011020202021100220101002 |
4 | 130030320321011212212233 |
5 | 112224111013434002142 |
6 | 1115443022052510515 |
7 | 35060642245234421 |
oct | 3414707105464657 |
9 | 537136667326332 |
10 | 124031023344047 |
11 | 3657a297217396 |
12 | 11ab206291b43b |
13 | 54290c960bc01 |
14 | 228b1c26c0811 |
15 | e514e8ecca32 |
hex | 70ce391669af |
124031023344047 has 2 divisors, whose sum is σ = 124031023344048. Its totient is φ = 124031023344046.
The previous prime is 124031023344001. The next prime is 124031023344073. The reversal of 124031023344047 is 740443320130421.
It is a strong prime.
It is a cyclic number.
It is not a de Polignac number, because 124031023344047 - 210 = 124031023343023 is a prime.
It is a self number, because there is not a number n which added to its sum of digits gives 124031023344047.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (124031023344247) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 62015511672023 + 62015511672024.
It is an arithmetic number, because the mean of its divisors is an integer number (62015511672024).
Almost surely, 2124031023344047 is an apocalyptic number.
124031023344047 is a deficient number, since it is larger than the sum of its proper divisors (1).
124031023344047 is an equidigital number, since it uses as much as digits as its factorization.
124031023344047 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 193536, while the sum is 38.
Adding to 124031023344047 its reverse (740443320130421), we get a palindrome (864474343474468).
The spelling of 124031023344047 in words is "one hundred twenty-four trillion, thirty-one billion, twenty-three million, three hundred forty-four thousand, forty-seven".
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