Base | Representation |
---|---|
bin | 11100001100111000111001… |
… | …000101100110101011001011 |
3 | 121021011020202021100220202121 |
4 | 130030320321011212223023 |
5 | 112224111013434004311 |
6 | 1115443022052512111 |
7 | 35060642245235305 |
oct | 3414707105465313 |
9 | 537136667326677 |
10 | 124031023344331 |
11 | 3657a297217624 |
12 | 11ab206291b637 |
13 | 54290c960c08c |
14 | 228b1c26c0975 |
15 | e514e8eccb71 |
hex | 70ce39166acb |
124031023344331 has 2 divisors, whose sum is σ = 124031023344332. Its totient is φ = 124031023344330.
The previous prime is 124031023344259. The next prime is 124031023344419. The reversal of 124031023344331 is 133443320130421.
It is a weak prime.
It is a cyclic number.
It is not a de Polignac number, because 124031023344331 - 213 = 124031023336139 is a prime.
It is a super-2 number, since 2×1240310233443312 (a number of 29 digits) contains 22 as substring.
It is not a weakly prime, because it can be changed into another prime (124031023344131) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 62015511672165 + 62015511672166.
It is an arithmetic number, because the mean of its divisors is an integer number (62015511672166).
Almost surely, 2124031023344331 is an apocalyptic number.
124031023344331 is a deficient number, since it is larger than the sum of its proper divisors (1).
124031023344331 is an equidigital number, since it uses as much as digits as its factorization.
124031023344331 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 62208, while the sum is 34.
Adding to 124031023344331 its reverse (133443320130421), we get a palindrome (257474343474752).
The spelling of 124031023344331 in words is "one hundred twenty-four trillion, thirty-one billion, twenty-three million, three hundred forty-four thousand, three hundred thirty-one".
• e-mail: info -at- numbersaplenty.com • Privacy notice • done in 0.072 sec. • engine limits •