Base | Representation |
---|---|
bin | 101111011011… |
… | …011011100001 |
3 | 212101200000222 |
4 | 233123123201 |
5 | 11140324441 |
6 | 1122252425 |
7 | 210452111 |
oct | 57333341 |
9 | 25350028 |
10 | 12433121 |
11 | 7022208 |
12 | 41b7115 |
13 | 276419c |
14 | 1919041 |
15 | 1158d4b |
hex | bdb6e1 |
12433121 has 2 divisors, whose sum is σ = 12433122. Its totient is φ = 12433120.
The previous prime is 12433117. The next prime is 12433153. The reversal of 12433121 is 12133421.
It is a weak prime.
It can be written as a sum of positive squares in only one way, i.e., 9388096 + 3045025 = 3064^2 + 1745^2 .
It is an emirp because it is prime and its reverse (12133421) is a distict prime.
It is a cyclic number.
It is not a de Polignac number, because 12433121 - 22 = 12433117 is a prime.
It is a Chen prime.
It is a self number, because there is not a number n which added to its sum of digits gives 12433121.
It is not a weakly prime, because it can be changed into another prime (12433021) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 6216560 + 6216561.
It is an arithmetic number, because the mean of its divisors is an integer number (6216561).
Almost surely, 212433121 is an apocalyptic number.
It is an amenable number.
12433121 is a deficient number, since it is larger than the sum of its proper divisors (1).
12433121 is an equidigital number, since it uses as much as digits as its factorization.
12433121 is an odious number, because the sum of its binary digits is odd.
The product of its digits is 144, while the sum is 17.
The square root of 12433121 is about 3526.0631021013. The cubic root of 12433121 is about 231.6648015538.
Adding to 12433121 its reverse (12133421), we get a palindrome (24566542).
The spelling of 12433121 in words is "twelve million, four hundred thirty-three thousand, one hundred twenty-one".
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