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12513263756351 is a prime number
BaseRepresentation
bin1011011000010111100010…
…1001000010010000111111
31122022020220212101110012012
42312011320221002100333
53120004131010200401
642340303005401435
72431024224654431
oct266057051022077
948266825343165
1012513263756351
113a94933196806
1214a11a286927b
136c9cc375a2a7
143139065c8651
1516a7732058bb
hexb6178a4243f

12513263756351 has 2 divisors, whose sum is σ = 12513263756352. Its totient is φ = 12513263756350.

The previous prime is 12513263756341. The next prime is 12513263756359. The reversal of 12513263756351 is 15365736231521.

Adding to 12513263756351 its reverse (15365736231521), we get a palindrome (27878999987872).

It is a strong prime.

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2k-12513263756351 is a prime.

It is a self number, because there is not a number n which added to its sum of digits gives 12513263756351.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (12513263756359) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 6256631878175 + 6256631878176.

It is an arithmetic number, because the mean of its divisors is an integer number (6256631878176).

Almost surely, 212513263756351 is an apocalyptic number.

12513263756351 is a deficient number, since it is larger than the sum of its proper divisors (1).

12513263756351 is an equidigital number, since it uses as much as digits as its factorization.

12513263756351 is an odious number, because the sum of its binary digits is odd.

The product of its digits is 3402000, while the sum is 50.

The spelling of 12513263756351 in words is "twelve trillion, five hundred thirteen billion, two hundred sixty-three million, seven hundred fifty-six thousand, three hundred fifty-one".