12513885957071 has 2 divisors, whose sum is σ = 12513885957072. Its totient is φ = 12513885957070.

The previous prime is 12513885957043. The next prime is 12513885957073. The reversal of 12513885957071 is 17075958831521.

It is a strong prime.

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2^k-12513885957071 is a prime.

Together with 12513885957073, it forms a pair of twin primes.

It is a Chen prime.

It is a junction number, because it is equal to n+sod(n) for n = 12513885956995 and 12513885957013.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (12513885957073) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 6256942978535 + 6256942978536.

It is an arithmetic number, because the mean of its divisors is an integer number (6256942978536).

Almost surely, 2^{12513885957071} is an apocalyptic number.

12513885957071 is a deficient number, since it is larger than the sum of its proper divisors (1).

12513885957071 is an equidigital number, since it uses as much as digits as its factorization.

12513885957071 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 21168000, while the sum is 62.

The spelling of 12513885957071 in words is "twelve trillion, five hundred thirteen billion, eight hundred eighty-five million, nine hundred fifty-seven thousand, seventy-one".