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1254541312049 is a prime number
BaseRepresentation
bin10010010000011000011…
…111010100000000110001
311102221012010210211120212
4102100120133110000301
5131023300033441144
62400154530113505
7156431463130424
oct22203037240061
94387163724525
101254541312049
114440589570a3
1218317b41b895
13913c216700c
1444a120399bb
15229780ce49e
hex124187d4031

1254541312049 has 2 divisors, whose sum is σ = 1254541312050. Its totient is φ = 1254541312048.

The previous prime is 1254541312019. The next prime is 1254541312091. The reversal of 1254541312049 is 9402131454521.

It is a weak prime.

It can be written as a sum of positive squares in only one way, i.e., 1198357143025 + 56184169024 = 1094695^2 + 237032^2 .

It is a cyclic number.

It is not a de Polignac number, because 1254541312049 - 216 = 1254541246513 is a prime.

It is a junction number, because it is equal to n+sod(n) for n = 1254541311997 and 1254541312015.

It is not a weakly prime, because it can be changed into another prime (1254541312019) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 627270656024 + 627270656025.

It is an arithmetic number, because the mean of its divisors is an integer number (627270656025).

Almost surely, 21254541312049 is an apocalyptic number.

It is an amenable number.

1254541312049 is a deficient number, since it is larger than the sum of its proper divisors (1).

1254541312049 is an equidigital number, since it uses as much as digits as its factorization.

1254541312049 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 172800, while the sum is 41.

The spelling of 1254541312049 in words is "one trillion, two hundred fifty-four billion, five hundred forty-one million, three hundred twelve thousand, forty-nine".