Base | Representation |
---|---|
bin | 111100001100000010… |
… | …1000100010101011001 |
3 | 110100121212022202000001 |
4 | 1320120011010111121 |
5 | 4104202232004122 |
6 | 135213352213001 |
7 | 12224003243233 |
oct | 1703005042531 |
9 | 410555282001 |
10 | 129253000537 |
11 | 4a8a7a49401 |
12 | 2107269a161 |
13 | c25b1baa0b |
14 | 63821b9253 |
15 | 35674aa527 |
hex | 1e18144559 |
129253000537 has 2 divisors, whose sum is σ = 129253000538. Its totient is φ = 129253000536.
The previous prime is 129253000531. The next prime is 129253000559. The reversal of 129253000537 is 735000352921.
It is the 146773-rd star number.
It is a weak prime.
It can be written as a sum of positive squares in only one way, i.e., 105038217216 + 24214783321 = 324096^2 + 155611^2 .
It is a cyclic number.
It is not a de Polignac number, because 129253000537 - 223 = 129244611929 is a prime.
It is a junction number, because it is equal to n+sod(n) for n = 129253000496 and 129253000505.
It is not a weakly prime, because it can be changed into another prime (129253000531) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 64626500268 + 64626500269.
It is an arithmetic number, because the mean of its divisors is an integer number (64626500269).
Almost surely, 2129253000537 is an apocalyptic number.
It is an amenable number.
129253000537 is a deficient number, since it is larger than the sum of its proper divisors (1).
129253000537 is an equidigital number, since it uses as much as digits as its factorization.
129253000537 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 56700, while the sum is 37.
The spelling of 129253000537 in words is "one hundred twenty-nine billion, two hundred fifty-three million, five hundred thirty-seven", and thus it is an aban number.
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