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130001233 = 220359011
BaseRepresentation
bin1111011111110…
…10100101010001
3100001121202011111
413233322211101
5231240014413
620522213321
73135664225
oct757724521
9301552144
10130001233
116742293a
1237654241
1320c1920b
14133a0785
15b62dd3d
hex7bfa951

130001233 has 4 divisors (see below), whose sum is σ = 130062448. Its totient is φ = 129940020.

The previous prime is 130001203. The next prime is 130001251. The reversal of 130001233 is 332100031.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2k-130001233 is a prime.

It is a Duffinian number.

It is not an unprimeable number, because it can be changed into a prime (130001203) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (17) of ones.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 27303 + ... + 31708.

It is an arithmetic number, because the mean of its divisors is an integer number (32515612).

Almost surely, 2130001233 is an apocalyptic number.

It is an amenable number.

130001233 is a deficient number, since it is larger than the sum of its proper divisors (61215).

130001233 is an equidigital number, since it uses as much as digits as its factorization.

130001233 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 61214.

The product of its (nonzero) digits is 54, while the sum is 13.

The square root of 130001233 is about 11401.8083214901. The cubic root of 130001233 is about 506.5813034762.

Adding to 130001233 its reverse (332100031), we get a palindrome (462101264).

The spelling of 130001233 in words is "one hundred thirty million, one thousand, two hundred thirty-three".

Divisors: 1 2203 59011 130001233